two bulbs A and B are rated 100w-120v and 10w-120v. they are connected across a 120v source in series. which will consume more energy
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GIVEN ;-
⇒ Bulb A is rated as = 100 w - 120 v
⇒Bulbs B is rated as = 10 w - 120 v
⇒ Two bulbs are connected across a source in series of = 120 v
TO FIND ;-
⇒ Which will consume more energy ?
SOL ;-
⇒ In the bulb A -
⇒ Volts = 120 v
⇒ Power = 100 w
⇒In the bulb B-
⇒ Volts = 120 v
⇒ Power = 10 w
Now let us find the resistance of the two bulbs -
⇒ R = V² / P
Let us find the resistance for the bulb A-
⇒ Bulb A ( R ) = 120 ² / 100 = 144 ohm
⇒ Bulb B ( r ) = 120 ² / 10 = 1440 ohm
Now we got the resistance for both the bulbs.
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To find the series combination , we need to use the below formula to find out it -
⇒ R = R₁ + R₂ =
= 144 + 1440
= 1584 ohm is the resistance in series combination.
So 10 watts bulb consume more energy because uses less power and also the amount o current flowing is less . Remember the formula - P=I x E.
⇒ Bulb A is rated as = 100 w - 120 v
⇒Bulbs B is rated as = 10 w - 120 v
⇒ Two bulbs are connected across a source in series of = 120 v
TO FIND ;-
⇒ Which will consume more energy ?
SOL ;-
⇒ In the bulb A -
⇒ Volts = 120 v
⇒ Power = 100 w
⇒In the bulb B-
⇒ Volts = 120 v
⇒ Power = 10 w
Now let us find the resistance of the two bulbs -
⇒ R = V² / P
Let us find the resistance for the bulb A-
⇒ Bulb A ( R ) = 120 ² / 100 = 144 ohm
⇒ Bulb B ( r ) = 120 ² / 10 = 1440 ohm
Now we got the resistance for both the bulbs.
-------------------------------------------------------------------------------------------------------
To find the series combination , we need to use the below formula to find out it -
⇒ R = R₁ + R₂ =
= 144 + 1440
= 1584 ohm is the resistance in series combination.
So 10 watts bulb consume more energy because uses less power and also the amount o current flowing is less . Remember the formula - P=I x E.
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