Question

two candidates attempt to solve a quadratic equation of the form x²+px+q=0. one starts with a wrong value of p and finds the roots to be 2 and 6. the other starts with a wrong value of q and finds the roots to be 2, -9. the correct roots are:
a. -3, 7
b. -3,-7
c. 3,10
d. -3, -10

Answer 1

by using the sum of roots =(x+y)
and prod of roots = (x*y)
u ll get the the answer
.
I have got all this ,, above
Might it helps u little