Question

two capacitor c1=2uf and c2=4uf are connected in series and a potential difference (p.d) of 1200v is applied across it the potential difference across 2uf will be

Answer 1

total capacitance =4/3
q=CV
q=1200×4/3
q=1600
V=q/V
V=1600/2
v= 800



800 volts

Answer 2

The potential difference across 2uf is 800v

Capacitor 1 = c1 = 2uf (Given)

Capacitor 2 = cw = 4uf (Given)

Potential difference = 1200v (Given)

Equivalent capacitance = c1 × c2/(c1 + c2)

= 2 × 4/ (2 + 4)

= 8/6  

= 4/3 uF

As Q = CV

where Q is the charge , C is the capacitance of capacitor and V is the potential difference.

Thus, Q circuit = equivalent capacitance of circuit attached capacitor × potential difference

Q = 4/3  × 1200

= 1600 uC

Q = CV , where, C = 2uF , Q = 1600 uc

Thus,

V = 1600uC/2u

= 800v

Thus, the potential difference across 2uf is 800v