two capacitor c1=2uf and c2=4uf are connected in series and a potential difference (p.d) of 1200v is applied across it the potential difference across 2uf will be
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Two capacitor c1=2uf and c2=4uf are connected in series and a potential difference (p.d) of 1200v is applied across it the potential difference across 2uf will be
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Answered by
50
total capacitance =4/3
q=CV
q=1200×4/3
q=1600
V=q/V
V=1600/2
v= 800
800 volts
q=CV
q=1200×4/3
q=1600
V=q/V
V=1600/2
v= 800
800 volts
Answered by
14
The potential difference across 2uf is 800v
Capacitor 1 = c1 = 2uf (Given)
Capacitor 2 = cw = 4uf (Given)
Potential difference = 1200v (Given)
Equivalent capacitance = c1 × c2/(c1 + c2)
= 2 × 4/ (2 + 4)
= 8/6
= 4/3 uF
As Q = CV
where Q is the charge , C is the capacitance of capacitor and V is the potential difference.
Thus, Q circuit = equivalent capacitance of circuit attached capacitor × potential difference
Q = 4/3 × 1200
= 1600 uC
Q = CV , where, C = 2uF , Q = 1600 uc
Thus,
V = 1600uC/2u
= 800v
Thus, the potential difference across 2uf is 800v
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