two capacitors of capacitance 3 microfarad and 6 microfarad are charged to potentials of 2 volt and 5 volt respectively these two charged capacitors are connected in series find the potential across each of the two capacitors now
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C1 =3 and C2 = 6
Equivalent C = 3×6/(6+3) = 2
Total potential V = 2+4=7V
Charge when connected in series Q = C×V = 2×7=14
V1 = Q/C1 = 14/3 = 4.66V
V2= Q/C2 =14/6 =2.33V.
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