Two cards are drawn one by one from a pack of cards. The probability of getting first card an ace and second a colored one is (before drawing second card first card is not placed again in the pack) [UPSEAT 1999; 2003]
A) \frac{1}{26} B) \frac{5}{52} C) \frac{5}{221} D) \frac{4}{13}
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which color is needed... first specify that
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Answer:
Step-by-step explanation:
There are total 52 cards
There are 4 aces from 52 cards
Probability of drawing first card as an ace,
P(a) = 4/52 = 1/13
Now, there are cards remaining out of which there are 51
There are 16 honoured cards(ace,king,queen,jack)
honour cards as one ace we have already drawn.
Now, there are 15 honoured cards
Probability of drawing an honour card,
P(b) = 15/51 = 5/17
So, the required probability
1/13 * 5/17 = 5/221
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