Two cars each of mass 1000kg are moving in a straight line but in opposite directions. the velocity of each car is 5m/s before the collision during which they stick together. what will be the velocity of the combined cars after collision
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Answered by
94
Given:
Mass of car 1 (m1) = 1000kg
Mass of car 2 (m2) = 1000kg
Initial velocity of car 1 (u1) = 5m/s
Initial velocity of car 2 (u2) = - 5m/s (-ve sign for opposite direction)
After collision, final velocity (v) =
m1u1 + m2u2 =m1v1 + m2v2
1000 x 5 + 1000 x -5 = v(1000 + 1000) ---------- (v1=v2 =v)
5000 - 5000 = 2000v
v = 0
So the velocity of the combined cars after collision is zero
Mass of car 1 (m1) = 1000kg
Mass of car 2 (m2) = 1000kg
Initial velocity of car 1 (u1) = 5m/s
Initial velocity of car 2 (u2) = - 5m/s (-ve sign for opposite direction)
After collision, final velocity (v) =
m1u1 + m2u2 =m1v1 + m2v2
1000 x 5 + 1000 x -5 = v(1000 + 1000) ---------- (v1=v2 =v)
5000 - 5000 = 2000v
v = 0
So the velocity of the combined cars after collision is zero
Answered by
33
given
m1=1000kg
m2=1000kg
u1=5m/s
u2=5m/s
combined velocity ( v)=?
according to law of conservation of momentum ,
m1u1 - m2u2 = (m1 + m2) v
(1000×5)-(1000×5)=(1000+1000)v
5000-5000=2000v
0=2000v
v=2000/0
v=0
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