Two cars leave at the same time, one from East to west and the other from West to East on the
road. The first car is moring at an average speed of 36 km hr and the second car is moving at a
of 72 km hr. The cars cross each other in 300 seconds. What was the original distance between
they started moving?
Answers
Answered by
0
Answer:
Distance travelled by the 1st car in 15 seconds = OA = (36×
18
5
)×15m=150m
Distance travelled by the 2nd car in 15 seconds = OB = (48×
18
5
)×15m=200m
∴ Distance between them after 15 seconds = AB =
OA
2
+OB
2
=
150
2
+200
2
=
22500+40000
=
62500
=250m
Answered by
0
Answer:
9000m
Step-by-step explanation:
A .36km/hr=10m/s( 36*1000/60*60)
B.72km/hr=20m/s(72*1000/60*60)
hence in 300 sec
A will cover distance=10*300=3000m
B will cover distance=20*300=6000m
total distance=original distance betn starting time=3000+6000=9000m
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