Question

Two charges are at a distance d apart. If a copper plate of thickness d/2 is kept between them, the effective force will be(a) F/2(b) zero(c) 2F(d) √2F

Answer 1

answer is b

because effective air separation between them becomes infinite so force becomes zero

plz mark as brainliest answer

Answer 2

Answer:

The effective force will be zero.

(b) is correct option.

Explanation:

Given that,

Thickness $t=\dfrac{d}{2}$

We need to calculate the force

Using formula of force

$F=\dfrac{kq^2}{d^2}$

If a copper plate is kept between them,

We know that,

The dielectric constant is infinity for conductive material.

$K=\infty$

We need to calculate the effective force

Using formula of force

$F=\dfrac{kq^2}{d^2}\times\dfrac{1}{K}$

$F=\dfrac{kq^2}{d^2}\times\dfrac{1}{\infty}$

$F = 0$

Hence, The effective force will be zero.