Question

Two charges each of magnitude Q are fixed at 2a distance apart. A third charge (-q of mass 'm') is placed at the mid point of the two charges ,now -q charge is slightly displaced perpendicular to the line joining the charges then find its time period.

Answer 1

Answer:

T=2π√[(ma^3)/(4KQq)]

Explanation:

Points to be known,

General equation of SHM: a=x•w^2

And formula for electrostatic force

Refer the attachement for detailed solution.

Hope this answer helped you✌️