two circles , each of radius 7cm, intersect each other. the distance between their centres is 7 root 2. find the area common to both the circles.
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Step-by-step explanation:
The centre distance is 7√2 which means that all angles are 90° (since all sides equal)
Now, area of square formed = 7^2 = 49
Area of left sector = (πr^2)/4 = (22/7)*49/4
= 22*7/4 = 38.5
When subtracted we have remaining area = 49 - 38.5 = 10.5 cm^2 (area of square - left sector)
So, required area = left sector area - remining area = 38.5-10.5 = 28 cm^2
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