Two circles with centres A and B intersect at C and D. Prove that ZACB= ZADB.
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Answer:
Step-by-step explanation:
Given: Two circles with centres A and B intersect at C and D.
To Prove : ∠ACB = ∠ADB.
Construction:
Join AC, AD, BC, BD and AB.
Proof :
In ∆ACB an ∆ADB,
AC = AD [Radii of the same circle]
BC =BD [Radii of the same circle]
AB = AB [Common] ∴ ∆ACB ≅ ∆ADB [By SSS]
∴ ∠ACB = ∠ADB. [By cpctc].
hope it helps....
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