Question

two coins are tossed simultaneously find the probability of getting the getting out come.
1.two tails
2.no tail
3.at least one tail

Answer 1

probability of 2 tails : 0 / 2
probability of no tail : 1 / 2 ( because of no tail then head ) .
probability of at least 1 tail : 1 / 2

Answer 2

Number of possible outcomes= 4 [HH, TT, HT, TH]

1. Number of favourable outcomes= 1 [TT]

Probability of getting two tails= Number of favourable outcomes/Number of possible outcomes

=1/4

2. Number of favourable outcomes= 1 [HH]

Probability of getting no tails= Number of favourable outcomes/Number of possible outcomes

=1/4

3. Number of favourable outcomes= 3 [TH, HT, TT]

Probability of getting at least one tail= Number of favourable outcomes/Number of possible outcomes

=3/4

Hope it helps! :)