Question

Two coins are tossed simultaneously, What is the probability of getting atmost one head???

Answer 1

Answer:

Number of favourable outcomes = 3 .

P(E) = No. of favourable outcomes / Total number of possible outcomes

P(E) = 3/4

So 3/4 is the answer.

Answer 2

Step-by-step explanation:

no. of total events= 4

they are - HH TH HT TT

favourable outcomes = HT TH TT

i.e. 3

probability=>

$\frac{3}{4}$

hope you get it ✌️