Question

Two complementary angles are in the ratio of 7:8 find the angles ​

Answer 1

Answer:

let the angles be 7x and 8x

according to the question

7x+8x=90°

=)15x=90°

=)x=6°

7x=7*6=42°

8x=8*6=48°

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Answer 2

Answer:

Question :

Two complementary angles are in the ratio of 7:8 find the angles .

Answer :

$let \: the \: ratio \: be \: taken \\ \: as \: 7x \: and \: 8x \\ \\ complementary \: angle \: has \: 90 \\ \\ then \\ \\ 7x + 8x = 90 \\ \\ 15x = 90 \\ \\ x = \frac{90}{15} = 6 \\ \\ \\ \\ therefore \\ \: the \: angles \: are \: \\ \\ 7x = 7 \times 6 = 42 \\ \\ 8 x = 8 \times 6 = 48 \\ \\ \\ Therefore \: to \: check \: = 42 + 48 = 90 \\ \\ therefore \\ \: the \: angles \: are \: found \: and \: checked$