Math, asked by kushagrswastik8042, 11 months ago

Two complementary angles differ by 14 degree. What is the larger angle.

Answers

Answered by MaheswariS
27

Answer:

\textsf{The larger angle is }\mathsf{52^{\circ}}

Step-by-step explanation:

\textsf{Let the two complementary angles be }\mathsf{\theta\;\&\;\;90^{\circ}-\theta}

\textsf{As per given data,}

\mathsf{\theta-(90^{\circ}-\theta)=14^{\circ}}

\implies\mathsf{\theta-90^{\circ}+\theta=14^{\circ}}

\implies\mathsf{2\theta-90^{\circ}=14^{\circ}}

\implies\mathsf{2\theta=90^{\circ}+14^{\circ}}

\implies\mathsf{2\theta=104^{\circ}}

\implies\mathsf{\theta=52^{\circ}}

\textsf{Other angle is }\mathsf{90^{\circ}-52^{\circ}=38^{\circ}}

\therefore\textsf{The larger angle is }\mathsf{52^{\circ}}

Answered by anshbansal1170
7

two complementary angles differ by 14 degrees the larger angle is

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