Question

two concentric circles are of radii 10 cm and 8cm R P and r q are tangent to the two circle from our if the length of Arc is 20 CM then find the length of RQ​

Answer 1

Let RP=tangent to bigger circle=24cm

And

RQ=Tangent to smaller circle.

At the point where the radius of the bigger circle meets the tangent,, a right angled triangle is formed.

The length PQ=10cm-8cm =2cm

We get triangle RPQ which is a right angled triangle.

We therefore use pythogras theorem to get the required length RQ which is the tangent of the smaller circle.

(24×24) + (2×2)=580cm2

Getting the square root of 580cm2

We get:24.0831cm

QR=24.0831CM

Find more details in the image

Answer 2

Step-by-step explanation:

hello users 

solution

In triangle OAD and OBD

OA = OB = 10 cm (Radius of larger circle)

And

OD = 6 cm ( Radius of smaller circle)

And

AD and BD are the length of tangents

And

AB = length of chord of larger circle 

Here

Using Pythagoras theorem 

H² = B² + P² 

Here

AD = BD =√ (OA² - OD²)  = √ (OB² -  OD² )

=> AD = √ (10² - 6²)  

= √ (100 - 36)

= √ 64 

= 8 cm 

=> AD = BD = 8 cm 

Hence 

the length of chord = AB

= AD + BD 

= 8 cm + 8 cm

= 16 cm

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