Question

Two consecutive even number are such as that half of larger number exceeds one-forth of smaller number by five then the larger number is

Answer 1

let first no.=x
second no.=x+1
according to question
$\frac{1(x + 1)}{2} = \frac{1x}{4} + 5 \\ \frac{1(x + 1)}{2} = \frac{x + 20}{4} \\ 2x + 40 = 4x + 4 \\ 2x = 36 \\ so \: x = 18$
so larger no.=x+1=18+1=19
I HOPE IT WILL HELP YOU

Answer 2

$\fcolorbox{yellow}{red}{ANSWER}$

$\frac{2x + 2}{2} = \frac{2x}{4} + 5 \\ \\ \frac{2x + 2}{2} = \frac{2x + 20}{4} \\ \\ 4x + 4 = 2x + 20 \\ \\ 2x = 16 \\ \\ x = 8$