Question

Two consecutive even numbers are such that half of the larger number exceed one forth of the larger number by 5.Then the larger number is

Answer 1

hope it helps . thus this is the ans for the so called question u have asked

Answer 2

$\huge\sf{\underline{\underline{Correct \: Question:-}}}$

1. Two consecutive even numbers are such that half of the larger exceeds one-fourth of the smaller by 5. Find the numbers.

$\huge\sf{\underline{\underline{To \: find:-}}}$

• The even numbers of the smaller by 5

$\huge\sf{\underline{\underline{Let,}}}$

• The required even numbers be x and x + 2

$\huge\sf{\underline{\underline{Given:-}}}$

$\sf\dfrac{1}{2}(x+2)-\dfrac{1}{4}x=5$

$\huge\sf{\underline{\underline{Solution:-}}} \\ \\ \sf⟹\dfrac{2x+4-x}{4}=5 \\ \sf{⟹x+4=20 \: \: i.e. \: x=20-4=16}$

→ Required numbers = x and x + 2

= 16 and 16 + 2 = 16 and 18