Math, asked by hoorainalam13, 2 months ago

Two consecutive positive number are such that the sum of their square is 113. Find the two numbers.

Please tell anyone with explanations

Answers

Answered by Anonymous
1

Answer:

56 and 57

Step-by-step explanation:

let the first number be x

and the second number be x+1

according to the question,

the sum of the numbers is 113

 \boxed{x + (x + 1) = 113}

 \boxed{2x + 1 = 113}

 \boxed{2x = 113 - 1}

 \boxed{2x  = 112}

 \boxed{x =  \frac{112}{2} }

 \boxed{x  = 56}

Hence the first number is 56 and second number is 56 + 1 = 57

Verification,

according to the question,

the sum of the numbers is 113

56 + 57 = 113

Similar questions