Math, asked by pawarsakshi0905, 5 months ago

Two dice are rolled probability of getting a total of 6 given that both faces are similar is​

Answers

Answered by Anonymous
3

Answer:

Assuming that the dice are unbiased or not " loaded".

Each side has the same probability, is 1/6 =0.16667, to turn up when rolled, if the die (D) is unbiased. The probability of a side turning up on D1 when 2 dice ( D1,D2) are rolled, is independent of the side turning up in D2. So this is an independent event.

How many ways can one get a sum total of 6 if D1 &D2 are rolled at the same time?

These are the possibilities

Case 1.

D1 =1 & D2=5

Or

D1= 5 & D2=1

Case 2.

D1 =2 & D2=4

Or

D1= 4 & D2= 2

Case 3. D1=3, D2=3

P3 =0.027778

Let's say, P 1 the probability for case 1 and P2 for case 2. There are no other cases.

The final probability P and is the sum total P = P1 + P2 + P3 the probability law of mutually exclusive events.

P1= 0.02778+ 0.02778 =0.055558

P2= 0.02778+0.02778 =0.055558

Same way,

P3=0.027778, when there is only one way to get the sum 6.

So, P = 0.138894

Step-by-step explanation:

Answered by nehabhosale454
21

Answer:

Open in App

Sign In

Quora uses cookies to improve your experience. Read More

What is the probability of getting a sum of 6 if two dice are thrown?

Ad by Wallarm

API security strategies 2021.

Explore strategies to secure cloud native application architectures.

Learn More

35 Questions and Answers

Sumedha Sengupta, Former Member : ASA, ASQC, Sigma XI

Answered 5 years ago · Author has 792 answers and 927.5K answer views

What is the probability of getting a sum of 6 if two dice are thrown?

Two dice

Assuming that the dice are unbiased or not " loaded".

Each side has the same probability, is 1/6 =0.16667, to turn up when rolled, if the die (D) is unbiased. The probability of a side turning up on D1 when 2 dice ( D1,D2) are rolled, is independent of the side turning up in D2. So this is an independent event.

How many ways can one get a sum total of 6 if D1 &D2 are rolled at the same time?

These are the possibilities

Case 1.

D1 =1 & D2=5

Or

D1= 5 & D2=1

Case 2.

D1 =2 & D2=4

Or

D1= 4 & D2= 2

Case 3. D1=3, D2=3

P3 =0.027778

Let's say, P 1 the probability for case 1 and P2 for case 2. There are no other cases.

The final probability P and is the sum total P = P1 + P2 + P3 the probability law of mutually exclusive events.

P1= 0.02778+ 0.02778 =0.055558

P2= 0.02778+0.02778 =0.055558

Same way,

P3=0.027778, when there is only one way to get the sum 6.

So, P = 0.138894

Based on truncating at the sixth decimal place.

A visual representation with two unbiased dice and the possible cases would also give the same result and is a short cut method. I like to derive from the basics.

42K viewsView 6 Upvoters

6

Related Questions (More Answers Below)

If two fair dice are thrown, what is the probability of getting a sum of 6 or 8?

1,072 Views

If two dice are thrown simultaneously, what is the probability of getting a sum of numbers less than 6?

1,581 Views

If two normal dice are thrown together, what is the probability of getting a sum of 7?

99,933 Views

Two dice are rolled. What’s the probability of a sum of 6 or 9?

7,094 Views

What is the probability of getting a sum of eight if two dice are thrown at once?

54,150 Views

Other Answers

John Abraham

Answered 1 year ago

What is the probability of getting a sum of 6 if two dice are thrown?

The answer would be 5/36 because the number of possible outcomes is 36, and the possible ways to get a sum of six are (1, 5), (2, 4), (3, 3), (4, 2), (5, 1). There are 5 ways and 36 possible outcomes in total, so 5/36 is the answer. There is one more solution as well (technically). The order could matter in this problem, so (3, 3) and (3, 3) can be perceived to be different. With this method of solving the problem, there would be 42 different outcomes and 6 ways to obtain a sum of six, making the answer 1/7. The reason (3, 3) and (3, 3) are different is because it would look like this with A being the first dice and B being the 2nd: (1A, 5B), (2A, 4B), (3A, 3B), (3B, 3A), (4A, 2B), and (5A, 1B). These two solutions can be both counted as correct based on the way that one perceives it. The second solution is obtained using permutations instead of simple combinations. The first solution (5/36) is widely regarded as the correct answer (which is mostly true), but technically 1/7 is also correct.

Similar questions