Two dice are thrown simultaneously find the probability of getting 1. A total of at least 10 2. A doublet of even number
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Total number of outcomes = 36
1) Desired Cases ={(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)}
Probability = 6/36 = 1/6
2) Desired cases = {(4,6),(5,5),(6,4),(6,6)}
Probability = 4/36 = 1/9
1) Desired Cases ={(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)}
Probability = 6/36 = 1/6
2) Desired cases = {(4,6),(5,5),(6,4),(6,6)}
Probability = 4/36 = 1/9
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