Math, asked by ratika4, 1 year ago

two dice are thrown simultaneously . find the probability that top face of the two dice show 1) different number 2) number greater then 5

Answers

Answered by Anonymous
0
Here is ur answer..........
total cases =36
sample space={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
                          (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
                            (3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
                         (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
                          (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
                           (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
1. probability of different numbers=no. of favourable outcomes/total no. of outcomes
                                                       =30/36=5/6
2. probability of no.any no. greater than 5=11/36
3. probability of bot no. greater than 5=1/36
hope this helps uh dear ...........
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