Two dice are thrown simultaneously. What is the probability that (I) 5 will not come up on either of them (2) 5 will come up on at least one (3) 5 will come up at both the dice
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Answer:
1 -1/12
2- 1/6
3- 2/12 =6
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Two dice thrown,
So, the total outcomes = 6² = 36
1. 5 will not come either of them
Favourable Outcomes = 36-12 = 24
P( not e) = Favorable outcomes/total Outcomes
= 24/36 = 2/3
2. 5 will come at least once
Favorable outcomes = 12
P(e) = Favorable outcomes/total Outcomes
=12/36 = 1/3
3. 5 will come both twice
Favourable Outcomes =2
P(e) = Favorable outcomes/total Outcomes
= 2/36
= 1/18
Hopefully it helps you...
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