Question

two dice are thrown together. find the probability that the product of the number the top of the dice is 6 , 12 ,7​

Answer 1

for 6---->

product (1,6)(6,1)(2,3)(3,2)

p(for getting 6) = 4/36

= 1/9

for 12---->

product (2,6)(6,2)(3,4)(4,3)

p(for getting 12) = 4/36

= 1/9

for 7----->

p( for getting 7) = 0

Answer 2

Answer:

i) for 6= 4/36=1/9

ii)for 12=4/36=1/9

iii)for 7=0/36=0