Question

two different dice are tossed together. find the probability taht the sum of numbers appearing on the two dice is 5.

Answer 1

Given that two dice are thrown = 6^2 = 36

Number of outcomes = {1,4},{2,3},{3,2},{4,1}

                                     = 4.


probability P(A) = 4/36

                          = 1/9.


Hope this helps!

Answer 2

hello users ....

solution:-
the number of outcomes when dice is tossed = 6² = 36

and
favorable out comes = { (1,4) , (2,3) , (3,2) , (4,1) }

=> number of favorable outcomes = 4 

Required probability = (no of favorable outcome ) / (total no. of outcomes) 

=> P( getting sum 5 ) = 4/36 
= 1/9 Answer

# hope it helps :)