Question

Two equal forces p and p acting at an angle 60°has a resultant 43.3 N.find the magnitude

Answer 1

magnitude of both forces = p

angle between them = 60°

resultaat = 43.3 N

$43.3 = \sqrt{ {p}^{2} + {p}^{2} + 2p \times p \times \cos(60) } \\ \\ 43.3 = \sqrt{ 2{p}^{2} + 2{p}^{2} \times \frac{1}{2} }$

$43.3 = \sqrt{3 {p}^{2} } \\ \\ 3 {p}^{2} = {43.3}^{2}$

$p = \sqrt{ \frac{ {43.3}^{2} }{3} } = 25$

Magnitude of force is 25N

Answer 2

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ĄNsWeR࿐}}}$

magnitude of both forces = p

angle between them = 60°

resultaat = 43.3 N

$43.3 = \sqrt{ {p}^{2} + {p}^{2} + 2p \times p \times \cos(60) } \\ \\ 43.3 = \sqrt{ 2{p}^{2} + 2{p}^{2} \times \frac{1}{2} }$

$43.3 = \sqrt{3 {p}^{2} } \\ \\ 3 {p}^{2} = {43.3}^{2}$

$p = \sqrt{ \frac{ {43.3}^{2} }{3} } = 25$

Magnitude of force is 25N