Question

Two equal opposite charges are placed at a certain distance apart and force of attraction between them is f. If 75% charge of one is transferred to another, then the force between the charges becomes

Answer 1

Answer:

7/16 F

Explanation:

suppose both charges are q and are d distance apart

so F = kq^2/r^2

now 75% of q is 3q/4

now charge in each particle is

q+3q/4. q-3q/4

7q/4. q/4

New force = k7qq/16r^2

Hence F"= 7F/16