Question

Two identical metal plates separated by a distance d form a parallel plate capacitor a metal sheet of thickness d/2 is inserted between the plates

Answer 1

CA = ε0A/d and CB -1 = 1/C1 + 1/C2

= d/4ε0A + d/4ε0A = d/2ε0A

⇒ CB = 2ε0A/d

So, CA/CB = 1/2

Two metal plates separated by a distance d constitute a parallel plate capacitor. A metal slab of thickness (d/2) and same area as the plate is inserted between the plates.