Physics, asked by harshbhushan9058, 10 months ago

Two friends, al and jo, have a combined mass of 137 kg. At an ice skating rink they stand close together on skates, at rest and facing each other, with a compressed spring between them. The spring is kept from pushing them apart, because they are holding each other. When they release their arms, al moves off in one direction at a speed of 1.18 m/s, while jo moves off in the opposite direction at a speed of 1.37 m/s. Assuming that friction is negligible, find al's mass.

Answers

Answered by AnmolRaii
0

Answer:

63.4 kg

Explanation:

This is a shock problem that must be solved with the conservation of the moment, for this we create a system formed by the two friends (Al and Jo) and the spring, so the forces that act are internal and the moment is conserved

Initial p₀ = 0

Final p_{f} = m₁ v₁ + m₂ v₂

Assign Al letter 1 and Jo letter 2

p₀ = p_{f}

0 = m₁ v₁ + m₂ v₂

m₁ / m₂ = - v₂ / v₁

m₁ / m₂ = - 1.37 / -1.18

m₁ / m₂ = 1,161

m₁ = 1,161 m₂

In addition, we combined mass

m₁ + m₂ = 137 Kg

(1,161 m₂) + m₂ = 137

2,161 m₂ = 137

m₂ = 63.4 kg

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