Two equal sides of an isosecles traingle are each 2cm more than thrice the third side if the perimeter of traingle is 67 cm. Find the lengths of an sides
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so smaller side is 9 and other 2 equal sides are each 29
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QUESTION ----- Two equal sides of an isosecles traingle are each 2cm more than thrice the third side if the perimeter of traingle is 67 cm. Find the lengths of an sides
ANSWER --------
Let the third side of the ∆ be x cm
Then, According to Question other two sides will be of length ( 3x + 2 ) cm
PERIMETER = SUM OF LENGTH OF ALL SIDES
67 cm = x + 3x + 2 + 3x + 2
67 = 7x + 4
7x = 67 - 4
7x = 63
x = 9 cm
ANSWER :
LENGTH OF THIRD SIDE = 9 cm
LENGTH OF OTHER TWO SIDES = 3 × 9 + 2
=> 27 + 2
= 29 cm
>>>>>>>>>>>>>>>>>>>>>>>>>>>
ANSWER --------
Let the third side of the ∆ be x cm
Then, According to Question other two sides will be of length ( 3x + 2 ) cm
PERIMETER = SUM OF LENGTH OF ALL SIDES
67 cm = x + 3x + 2 + 3x + 2
67 = 7x + 4
7x = 67 - 4
7x = 63
x = 9 cm
ANSWER :
LENGTH OF THIRD SIDE = 9 cm
LENGTH OF OTHER TWO SIDES = 3 × 9 + 2
=> 27 + 2
= 29 cm
>>>>>>>>>>>>>>>>>>>>>>>>>>>
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