Question

Two equal small metal balls charged to + 5 and – 15 units are brought together and allowed to touch each other than they are separated as before, the ratio between the forces in the two case

Answer 1

Answer:

Charge is conserved so

Q1+Q2=Q3+Q4

Q1 and Q2 are initial charges and Q3 and Q4 are charges after connecting them

Q3=Q4=Q ( they are identical )

So Q=

2

10+20

Q=15C

Ratio of forces =K(10)(20):K(15)(15)

8:9

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