Two forces of 20 N and 10 N are making an angle of 120° with each other. Find a single pull that would (a) replace the given forces system (b) balance the given forces system. ((a)FR = 17.32 N, OR = 30°, (b) FR = 17.32 N, OR = 210°)
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Explanation:
Let, P and Q be the two forces having magnitudes 15 Newtons and 20 Newtons respectively. They are acting at an angle α = 60°.
Let, R be the resultant vector. Vector R acts at an angle θ with vector P.
So, |R^2| = 15^2 + 20^2 + 2 * 15 * 20 * cos 60°
Or, |R^2| = 225 + 400 + 300 = 925
Or, |R| = 30.4138 Newtons
So, tan θ = (20 * sin 60°) / {15 + 20 * cos 60°}
Or, tan θ = (10√3) / (15 + 10) = (10√3) / 25
Or, tan θ = (2√3) / 5 = 0.69282
Or, θ = 34.715°
So, magnitude of the resultant force = 30.4138 Newtons and the resultant force acts at an angle 34.715° with the 15 Newton magnitude force.
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