Question

two forces of 4N act on a body at an angle of 60degree. Find magnitude and direction of the resultant force acting on the body ​

Answer 1

Answer:

fcostheta = 2

fsintheta = 2√3

As fsintheta is more the force is in direction of fsinththeta

Answer 2

Answer:

For this you draw a right angle (90 degrees, perpendicular) triangle, with the two adjacent legs at 3N and 4N respectively. Then the crosswise leg (hypotenuse, opposite side) will have a length of the square root of 3N squared plus 4N squared, i.e. 5N. [3x3 + 4x4 = 9+16 = 25 = 5x5]. One more thing: The angle of the resultant will be the vector sum of the two forces; that angle will be the inverse tangent of 3/4 or 0.75.... hmm, look it up online or on my calculator: 36.86989765 degrees (about 37 degrees) or 0.64350111 radians. There are usually several ways to solve most problems like this; the result should be the same, but it can be expressed using different units.