two forces whos magnitude are in ratio 3:5 give resultant 28N . if the angle of inclination is 60° find the magnitude of each
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Let A and B be the two forces.
Then, A = 3x, B = 5x, R = 28 N and $\theta$ = 60°
Thus, A/B = 3/5
R=(A^2+B^2+2ABCOS$THETH$)^2
R=(9x^2+25x^2+30x^2.COS60
=R=28=7x
x=4
.’.Forces are A = 12 N B = 20 N
Then, A = 3x, B = 5x, R = 28 N and $\theta$ = 60°
Thus, A/B = 3/5
R=(A^2+B^2+2ABCOS$THETH$)^2
R=(9x^2+25x^2+30x^2.COS60
=R=28=7x
x=4
.’.Forces are A = 12 N B = 20 N
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