two forces whose magnitude are in ratio 3:5 give a resultant of 35N if the angle of inclination between the forces is 60° find the magnitude of forces
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given
F1/F2 = 3/5
F2 = 5/3(F1) _____(1)
R = 35 N
@ = 60°
by parallelogram law of vector addition we have
R = ✓[(F1)^2 + (F2)^2 + 2|F1|•|F2|•cos@
35 = ✓[(F1)^2 + 25/9(F1)^2+ 10/3(F1)^2•cos60
35 = F(1)•√[1+25/9+10/3×1/2]
F(1) = 35/2.33
F(1) = 15.021 N
and from eqn (1)
F(2) = 5/3(15.021) = 25.025 N
F1/F2 = 3/5
F2 = 5/3(F1) _____(1)
R = 35 N
@ = 60°
by parallelogram law of vector addition we have
R = ✓[(F1)^2 + (F2)^2 + 2|F1|•|F2|•cos@
35 = ✓[(F1)^2 + 25/9(F1)^2+ 10/3(F1)^2•cos60
35 = F(1)•√[1+25/9+10/3×1/2]
F(1) = 35/2.33
F(1) = 15.021 N
and from eqn (1)
F(2) = 5/3(15.021) = 25.025 N
priyu9:
thank you
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