Question

two forces with equal magnitude F acts on a body and the magnitude of resultant force is F/3 the angle between the two forces is

Answer 1

Let both the equal forces be F

The resultant​ will be

= √(F² + F² + 2F.F.cos(θ)) (θis the angle​ between the forces)

=√(2F² + 0) (cos(90) is 0)

=√2.F

=> √2.F = 1414

=> F = 1.414*1000/√2

=> F = 1000N

#hope it helps

Answer 2

(F/3)^2=F^2+F^2+2Fcosx
F^2/9=F^2+F^2+2Fcosx
F^2/9=F^2(1+1+2cosx)
1/9=2(1+cosx)
x°=cos^-1(-17/18)