two forces with equal magnitude F acts on a body and the magnitude of resultant force is F/3 the angle between the two forces is
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Answered by
2
Let both the equal forces be F
The resultant will be
= √(F² + F² + 2F.F.cos(θ)) (θis the angle between the forces)
=√(2F² + 0) (cos(90) is 0)
=√2.F
=> √2.F = 1414
=> F = 1.414*1000/√2
=> F = 1000N
#hope it helps
Answered by
9
(F/3)^2=F^2+F^2+2Fcosx
F^2/9=F^2+F^2+2Fcosx
F^2/9=F^2(1+1+2cosx)
1/9=2(1+cosx)
x°=cos^-1(-17/18)
F^2/9=F^2+F^2+2Fcosx
F^2/9=F^2(1+1+2cosx)
1/9=2(1+cosx)
x°=cos^-1(-17/18)
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