Question

two glass bulbs of equal volume are connected by a narrow tube and are filled with a gas at stp when one bulb is kept in melting ice and the other is placed in a hot bath, the new pressure is 877.6 mm of hg calculate temperature

Answer 1

Answer:

At first, at 273K

the mole in each bulb =

2

n

total

=

2

1

.

RT

P.2V

=

273×R

76V

On heating second bulb, some mole of gas are transferred to another bulb until the pressure of both bulb become same.

∴n

1=273R

P×Vand n

2 = R×335

PV

n ttota =n

1 +n 2

⇒2×

273R

76v

= 273R

P×V + 335×R

PP

⇒P=83.75 unit of Ag.

Explanation:

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