Science, asked by pleasehelpme36, 9 months ago

Two hockey pucks, each with a mass of 0.15 kg, slide across the ice and collide. Before the collision, puck 1 is moving 14 m/s to the west and puck 2 is moving 10 m/s to the east. After the collision, puck 1 is moving at 10 m/s to the east. What is the velocity of puck 2?

A. 14 m/s west
B. 10 m/s east
C. 10 m/s west
D. 14 m/s east

Answers

Answered by Rameshjangid
0

Answer:

The velocity of puck 2 is 705 m/s.

Explanation:

Step 1: Velocity and speed describe how quickly or slowly an object is moving. We frequently encounter circumstances when we must determine which of two or more moving objects is going faster. If the two are travelling on the same route in the same direction, it is simple to determine which is quicker. It is challenging to identify who is moving the quickest when their motion is in the other direction. The idea of velocity is useful in these circumstances. Learn what velocity is, how it is measured, an example of velocity, and how it differs from speed in this article.

Step 2: The pace at which an object's location changes in relation to a frame of reference and time is what is meant by velocity. Although it may appear sophisticated, velocity is just the act of moving quickly in one direction. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction. Its SI equivalent is the metre per second (ms^{-1}). A body is considered to be accelerating if its velocity changes, either in magnitude or direction.

Step 3: \vec{v}_{c m}=\frac{m_1 \overrightarrow{v_1}+m_2 \vec{v}_2}{m_1+m_2}

\frac{015 \times 14+0.15 \times 10}{0.3}

$$\begin{aligned}& 15 \times 14+0.15 \times 10=211.5 \\& =\frac{211.5}{0.3}\end{aligned}$$

Divide the numbers:\frac{211.5}{0.3}=705$

=705 m/s

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