Question

Two Horizontal forces 12N and 8N act on body of mass 4kg Minimum value of acceleration produced can n less than ​

Answer 1

Given:

Two Horizontal forces 12N and 8N act on body of mass 4kg.

To find:

Minimum value of acceleration ?

Calculation:

• Force will be minimum when the horizontal forces will act opposite to one another (i.e. at 180° to one another).

$F_{min} = 12 - 8 = 4N$

• So, minimum acceleration will be minimum force divided by the mass of the object.

$\implies \: a_{min} = \dfrac{ F_{min} }{m}$

$\implies \: a_{min} = \dfrac{4 }{4}$

$\implies \: a_{min} = 1 \: m/ {s}^{2}$

So, minimum acceleration is 1 m/s².