Two identical capacitors of capacitance c1 and c2 are connected in series
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Assume capacitance of two identical capacitors are ;
C(1) = a μF
C(2) = a μF
Since the two capacitors are arranged in series combination and identical , so their capacitance will be same.
C(1)= C(2) =a μF
1/C(total) = 1/C(1) + 1/C(2)
Substituting the values;
1/C(total) = [1/a+ 1/a] μF = 2/a μF
C(total) = a/2 μF
The total capacitance of the combination is a/2 μF.
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