Question

Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that ′O′ is their common point for the two. The wires carry I1 and I2 currents, respectively. Point 'I' is lying at distance 'd' from 'O' along a direction perpendicular to the plane containing the wires. The magnetic field at the point 'P' will be :

Answer 1

Answer:

Explanation:

"The magnetic field at point P which is at perpendicular distance d from O and is in perpendicular to the plane ABCD due to currents via COB and COD and are perpendicular to each other

B1=μ02πI1dB1=μ02πI1d acting in the plane of paper downwards.

B2=μ02πI2dB2=μ02πI2d acting in the plane of paper towards right.

∴B=B21+B22‾‾‾‾‾‾‾‾√=μ02πd

"

Answer 2

• The magnetic field at the point P at a perpendicular distance d from O in a direction perpendicular to the plane ABCD due to currents through COB & COD are perpendicular to each other.