Two identical piano wires, kept under the same tension T have a fundamental frequency of 600 Hz. The fractional increase in the tension of one of wires which will lead to the occurence of 6 beats per second when both the wires oscillate together would be
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Answered by
91
We want one of the wires to alter the frequency by 6 Hz = 0.01 or 1%
frequency f = √[ T /μ ]
relative errors: Δf/f = 1/2 * ΔT/T + 1/2 * Δμ /μ
Δf / f = 0.01 => ΔT/T = 0.02 as μ = constant.
The fractional increase 0.02 or 2%
frequency f = √[ T /μ ]
relative errors: Δf/f = 1/2 * ΔT/T + 1/2 * Δμ /μ
Δf / f = 0.01 => ΔT/T = 0.02 as μ = constant.
The fractional increase 0.02 or 2%
Answered by
22
V= frequency.
V=1/2L (T/U) ^1/2. (formula) Now, delta v/v=1/2delta T/T delta T/T=2delta v/v. 2*6/600. =0.02
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