Question

Two identical resistors each of resistance 10 ohm are connected in series and then in parallel, in line to a battery of 6 volts. calculate the ratio of power consumed in the combination of resistors in the two cases.

Answer 1

power= V^2/R

in series
Req=20

Power1 =6×6/20 =36/20

in parallel
Req =5

Power2 = 6×6/5 =36/5

so ratio of power

P1/P2= 36/20/36/5
it gives
P1 : P2 =1 :4

Answer 2

1)in series
10+10 = 20 ohm
Now find the current
I=V/R
=6/20
=0.3A
Now power
P1=V(I)
=6×0.3
=1.8W
2) in parallel
1/R=1/R+1/R
=1/10+1/10
R=5 ohm
Now current
I=V/R
=6/5
=1.2A
Power
P2=V×I
=6×1.2
=7.2W


Ratio
P1/P2=1.8/7.2
=0.25 W

Hope this helps you buddy