Question

two lines 3x-2y=5 and 2x+ky=7 are perpendicular to each other then find the value of k ?

Answer 1

Answer:

Step-by-step explanation:

3x-2y=5

-2y=5-3x

-y=5-3x/2

y=5+3x/2

So m1=3/2

Now

2x+ky=7

Ky=7-2x

y=7-2x/k

so

M2=-2/k

As we know that the perpendicular would be

m1×m2=-1

3/2×-2/k=1

3×-1/k=1

-3=k

Hope it helps u