Question

two liquids of densities 3 kg upon metre cube and 4 kg per metre cube are mixed together if their masses are equal then the density of mixture is

Answer 1

D = M1 + M2 / (M1/d1 + M2/d2) = 2/(1/3+1/4) = 2/(7/12) = 24/7 kg/m^3

Answer 2

Answer:

The density of mixture would be 3.43 kg per meter cube

Explanation:

Two liquids of densities 3 kg upon metre cube and 4 kg per metre cube.

Let mass of liquid 1 be "m" and mass of liquid 2 be "m"

Formula: $\text{Density }(\rho)=\dfrac{m}{V}$

Volume of liquid 1,  $V_1=\dfrac{m}{3}$

Volume of liquid 2,  $V_2=\dfrac{m}{4}$

After mixing two liquid

Volume of mixture is V

Mass of mixture would be m+m = 2m

Let density of mixture be σ

Thus,

$V=V_1+V_2$

$\dfrac{2m}{\rho}=\dfrac{m}{3}+\dfrac{m}{4}$

$\dfrac{2}{\rho}=\dfrac{1}{3}+\dfrac{1}{4}$

$\rho=\dfrac{24}{7}\approx 3.43\text{ kg/m}^3$

Hence, The density of mixture would be 3.43 kg per meter cube