Question

two men A and B can paint a house in 18 days they work together for 8 days and then B goes away and A alone finishes the work in 15 days how long would each of them take a finish the work separately

Answer 1

8/18 =4/9

remaining work to do is 5/9

so,5/9=15

thus 9×3=27

Answer 2

A can complete the work in 27 days and B can work in 54 days.

Step-by-step explanation:

Consider the provided information.

A and B can paint a house in 18 days they work together for 8 days.

The work done by them is: $\frac{1}{18}\times8=\frac{4}{9}$

The remaining work is $1-\frac{4}{9}=\frac{5}{9}$

$\frac{5}{9}$ th work is done in 15 days.

Therefore, time taken by A to complete the work alone is: $\frac{9}{5}\times15=27$

Hence, A complete the work in 27 days.

B can complete the work in:

$\frac{1}{18}-\frac{1}{27} =\frac{1}{54}$

Hence, B can complete the work in 54 days.

A can complete the work in 15 days and B can work in 54 days.

#Learn more

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