two men of masses m and m/2 starts climbing up on two massless string fixed at the ceiling with acceleration g and g/2 respectively. the ratio of tensions in the two string will be:
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Answered by
8
1st men:
force(tension)= m × a
= m×g
2nd men:
f = m × a
= m/2 × g/2
= mg/4
ratio = mg / (mg/4)
= 4:1
force(tension)= m × a
= m×g
2nd men:
f = m × a
= m/2 × g/2
= mg/4
ratio = mg / (mg/4)
= 4:1
Answered by
4
Answer:8:3
Explanation:
For man 1:
Tension in string=mg+mg=2mg
For man 2:
Tension in string=m/2*g+m/2*g/2=3mg/4
Ratio:
2mg/3mg/4=8:3
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