Question

two metallic wires of the same material are connected in parallel. wire a has length "l" and radius r, wire b has a length 2l and radius 2r . calculate the ratio of their equivalent resistance in parallel combination and the resistance of wire A.​

Answer 1

Explanation:

Details about Wire of A:-

Length = l.

Radius =r.

Area =π r2.

R1= rho x l /π r2.

Details about the wire 2:-

Length = 2l.

Radius = 2r.

Area = π 4r2.

R2= rho x 2l/π 4r2=rho x l /π x 2r2.

Total resistance of the circuit:-

1/Rp= 1/R1+1/R2.= πr2/rho x l+2 π r2/ rho x l.=3 π r2/rho x l.

Rp= rho x l/ 3 π x r2.

Rp/ R1= rho /3π r2 ÷rho x 1 / πx r2.

Rp : R1= 1 : 3

Hope it will help you

✌️sai

Answer 2

⭐《ANSWER》

$\huge\mathfrak\pink {ANSWER}$

↪Actually welcome to the Concept of the CURRENT ELECTRICITY

↪since here we know that,

↪R = rho * l/A

↪now here , the Resistance for Wire A = rho * l/A

↪and the equivalent resistance after solving we get as

↪Req = rho * l/3A

↪Now finding ratio , we get as

〽RA / Req = 3:1