Question

two natural numbers differ by 6 and the sum of them is 36. Find the larger number​

Answer 1

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Let one number be x , then, another number = x+6( since the other number is 6 greater than the first)

Now, given that :

$x + x + 6 = 36$

Solving the given equation :

$\implies \: x + x + 6 = 36$

$\implies2x + 6 = 36$

$\implies2x = 36 - 6 = 30$

$\implies x = \frac{30}{2} = 15$

Now we know, x = 15

Therefore, the greater number = x + 6 = 21

Verification :

x + (x + 6) = 36

15 + (15 + 6) = 36

15 + 21 = 36

Hence verified ✔️