Question

two no. when multiplied the result is 8 and when the two no. are added the result is 11
Find the two no.​

Answer 1

Explanation:

let one no. be x and the other be y

ATQ,

x+y = 11

therefore,

x= 11 - y. -------------1

Again ATQ

x × y = 8

From ----1

(11-y) ×y =8

11y -y^2 = 8

-y^2 + 11y - 8 =0

- (y^2 - 11y + 8) = 0

the question can't be solved further. Please check the question again.

Answer 2

Answer:

let one no. be x and the other will be 11 - x

Because, x + number2 = 11

therefore,

Number 2 = 11 - x

Given : x × (11 - x) = 8

(11-x) ×x =8

11x -x^2 = 8

Or x^2 - 11x +8 = 0

Unable to solve it further

Recheck your question plz